`[NiCl_(4)]^(2-)` is paramagnetic while `[Ni(CO)_(4)]` is diamagnetic though both are tetrahedral Why?

Explanation

To understand why `[NiCl_(4)]^(2-)` is paramagnetic while `[Ni(CO)_(4)]` is diamagnetic, despite both being tetrahedral, we need to analyze the electronic configurations and the nature of the ligands involved.

### Step-by-Step Solution:

1. **Identify the Oxidation State of Nickel in Both Complexes**:
- For `[NiCl_(4)]^(2-)`:
- Chlorine (Cl) has a charge of -1.
- Let the oxidation state of Ni be \( x \).
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