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A train starting from a railway station and moving with uniform acceleration attains a speed `40 km//h` in `10` minutes. Find its acceleration.

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To find the acceleration of the train, we can follow these steps: ### Step 1: Identify the given values - Initial velocity (u) = 0 m/s (since the train starts from rest) - Final velocity (v) = 40 km/h - Time (t) = 10 minutes ### Step 2: Convert the final velocity from km/h to m/s ...
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Knowledge Check

  • A train starting from rest, and moving with uniform acceleration alpha , acquires a speed v. Then its comes to a stop with uniform retardation beta . Then the average velocity of the train is

    A
    `v//2`
    B
    `v//4`
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    `(alpha + beta)t//2`
    D
    `(alpha + beta)t//alphabeta`

  • Starting from rest a body moves with uniform acceleration and acquires a velocity v after n seconds. Then its displacement in the last two seconds is

    A
    `2 v(n + 1)//n`
    B
    `2 v(n-1)//n`
    C
    `2v(n + 1)^(2)//n`
    D
    `v(n-1)^(2)n`

  • A body starts from rest and moves with a uniform acceleration. The ratio of the distance covered in the nth sec to the distance covered in n sec is

    A
    `(2)/(n) - (1)/(n^(2))`
    B
    `(1)/(n^(2)) - (1)/(n)`
    C
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