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A train is travelling at a speed of 90 k...

A train is travelling at a speed of `90 km//h`. Brakes are applied so as to produce a uniform acceleration of `- 0.5 m//s^(2)`. Find how far the train will go before it is brought to rest.

Text Solution

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Initial speed of the train, u = 90 km/h = 25 m/s
Final speed of the train, v = 0 (finally the train comes to rest)
Acceleration = -0.5 m `s^(2)`
According to third equation of motion :
`v^(2)=u^(2) +2 as`
`(0)^(2)=(25)^(2)+ 2 (-0.5)s`
Where, s is the distance covered by the train
`S=(25^(2))/(2(0.5))=625 m `
The train will cover a distance of 625 m before it comes to rest.
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