Home
Class 9
PHYSICS
A trolley, while going down an inclined ...

A trolley, while going down an inclined plane, has an acceleration of `2 cm//s^(2)` starting from rest. What will be its velocity `3 s` after the start ?

Text Solution

AI Generated Solution

To solve the problem, we need to find the velocity of a trolley after 3 seconds of starting from rest while moving down an inclined plane with a given acceleration. ### Step-by-Step Solution: 1. **Identify the Given Values:** - Initial velocity (u) = 0 cm/s (since it starts from rest) - Acceleration (a) = 2 cm/s² - Time (t) = 3 s ...
Promotional Banner

Topper's Solved these Questions

  • MOTION

    NCERT ENGLISH|Exercise Exercise|10 Videos
  • FORCE AND LAW OF MOTION

    NCERT ENGLISH|Exercise All Questions|36 Videos
  • SOUND

    NCERT ENGLISH|Exercise Exercise|39 Videos

Similar Questions

Explore conceptually related problems

A racing car has a uniform acceleration of 4 m//s^(2) . What distance will it cover in 10 s after start ?

A body has an initial velocity of 3 ms^-1 and has an acceleration of 1 ms^-2 normal to the direction of the initial velocity. Then its velocity 4 s after the start is.

A solid sphere of mass 0.1kg and radius 2cm rolls down an inclined plane 1.4m in length (slope 1 in 10). Starting from rest, what will be its final velocity?

The displacement of a body in 8 s starting from rest with an acceleration of 20 cms^(-2) is

Find the angular velocity of a body rotating with an acceleration of 2rev/s^2 as it completes the 5th revolution after the start

An uniform spherical shell of mass m and radius R starts from rest with pure rolling on long inclined plane as shown in figure. The angular momentum of shell about point of contact after 1 s of its starting is KmR. Determine the value of k(g=10m//s^(2)) .

A particle starting from rest attains a velocity of 50 ms^(-1) in 5 s. The acceleration of the particle is

A car, starting from rest, moves in a straight line with constant acceleration . 4m//s^(2) After some time, it immediately starts retarding at constant rate 2m//s^(2) until it comes to rest. If the car moved for a total time 18 seconds, the total distance covered is

The velocity of an object at t =0 is vecv_(0) =- 4 hatj m/s . It moves in plane with constant acceleration veca = ( 3hati + 8 hatj) m//s^(2) . What is its velocity after 1 s?

A block of mass 1 kg slides down a rough inclined plane of inclination 60^(@) starting from its top. If coefficient of kinetic is 0.5 and length of the plane d=2 m, then work done against friction is