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A stone is thrown in a vertically upward...

A stone is thrown in a vertically upward direction with a velocity of `5 m//s`. If the acceleration of the stone during its motion is `10 m//s^(2)` in the downward direction, what will be the height attained by the stone and how much time will take to reach there ?

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AI Generated Solution

To solve the problem step by step, we will use the equations of motion. Here’s how we can find the height attained by the stone and the time taken to reach that height: ### Step 1: Identify the given values - Initial velocity (u) = 5 m/s (upward) - Final velocity (v) = 0 m/s (at the highest point) - Acceleration (a) = -10 m/s² (downward) ### Step 2: Use the equation of motion to find the height (s) ...
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