An object of mass 15kg is moving with a uniform velocity of 4m/s. what is the kinetic energy possessed by the object ?

Options

A. `100J`
B. `120J`
C. `130J`
D. `140J`

Explanation

To find the kinetic energy possessed by an object, we can use the formula for kinetic energy (KE):

\[ KE = \frac{1}{2} mv^2 \]

where:
- \( m \) is the mass of the object (in kilograms),
- \( v \) is the velocity of the object (in meters per second).

### Step-by-Step Solution:

1. **Identify the mass of the object**:
- Given mass \( m = 15 \, \text{kg} \).

2. **Identify the velocity of the object**:
- Given velocity \( v = 4 \, \text{m/s} \).

3. **Substitute the values into the kinetic energy formula**:
\[ KE = \frac{1}{2} \times m \times v^2 \]
\[ KE = \frac{1}{2} \times 15 \, \text{kg} \times (4 \, \text{m/s})^2 \]

4. **Calculate \( v^2 \)**:
\[ v^2 = 4 \, \text{m/s} \times 4 \, \text{m/s} = 16 \, \text{m}^2/\text{s}^2 \]

5. **Substitute \( v^2 \) back into the kinetic energy formula**:
\[ KE = \frac{1}{2} \times 15 \, \text{kg} \times 16 \, \text{m}^2/\text{s}^2 \]

6. **Calculate \( \frac{1}{2} \times 15 \, \text{kg} \)**:
\[ \frac{1}{2} \times 15 = 7.5 \, \text{kg} \]

7. **Now multiply by \( 16 \, \text{m}^2/\text{s}^2 \)**:
\[ KE = 7.5 \, \text{kg} \times 16 \, \text{m}^2/\text{s}^2 = 120 \, \text{kg} \cdot \text{m}^2/\text{s}^2 \]

8. **Convert to Joules**:
- Since \( 1 \, \text{kg} \cdot \text{m}^2/\text{s}^2 = 1 \, \text{J} \),
\[ KE = 120 \, \text{J} \]

### Final Answer:
The kinetic energy possessed by the object is **120 Joules**.

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