Home
Class 9
PHYSICS
The mass of the earth is 6 × 10^(24) kg ...

The mass of the earth is `6 × 10^(24)` kg and that of the moon is` 7.4 xx 10^(22)` kg. If the distance between the earth and the moon is `3.84xx10^(5)` km, calculate the force exerted by the earth on the moon. (Take G `= 6.7 xx 10^(–11) N m^(2) kg^(-2)`)

Text Solution

Verified by Experts

the mass ofhte earth ,`M=6xx10^(24)`kg
the mass of the moon ,
`m=7.4xx10^(22)`
the distance between the earth and the moon,
`d=3.84xx10^(5) km`
`=3.84xx10^(5)xx1000m`
`=3.84xx10^(8)m`
`G=6.7xx10^(-11) Nm^(2) kg^(-2)`
From Eq . (10.4) ,the force exerted by the earth on the moon is
`F=G(Mxxm)/(d^(2))`
`=(6.7xx10^(-11) Nm^(2) kg^(-2) xx6xx10^(24)kg xx7.4xx10^(22)kg)/((3.84xx10^(8)m)^(2))`
`=2.02xx10^(20)`N.
Rhus the force exerted by the earth on the moon is `2.02xx10^(20)` N.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • FORCE AND LAW OF MOTION

    NCERT ENGLISH|Exercise All Questions|36 Videos

Similar Questions

Explore conceptually related problems

Find the distance of a point from the earth's centre where the resultant gravitational field due to the earth and the moon is zero The mass of the earth is 6.0 xx 10^(24)kg and that of the moon is 7.4 xx 10^(22)kg The distance between the earth and the moon is 4.0 xx 10^(5)km .

Mass of moon is 7.349 xx 10^(22) kg and its radius is 1.738 xx 10^(6) m . Calculate its mean density and acceleration due to gravity on its surface. Given G = 6668 xx 10^(-11) Nm^(2) kg ^(-2) .

Knowledge Check

  • The mass of the earth is 6xx10^(24)kg and that of the moon is 7.4xx10^(22)kg . The potential energy of the system is -7.79xx10^(28)J . The mean distance between the earth and moon is (G=6.67xx10^(-11)Nm^(2)kg^(-2))

    A
    `3.8xx10^(8) m`
    B
    `3.37xx10^(6)` m
    C
    `7.60xx10^(4)` m
    D
    `1.9xx10^(2)` m

    • Similar Questions

    Explore conceptually related problems

    Calculat the binding energy of the - sum system . Mass of the earth =6xx 10 ^(24) kg , mass of the sun = 2 xx 10^(30) kg, distance between the earth and the sun = 1.5 xx 10^(11) and gravitational constant = 6.6 xx 10 ^(-11) N m^(2) kg^(2)

    If the acceleration due to gravity on earth is 9.81 m//s^(2) and the radius of the earth is 6370 km find the mass of the earth ? (G = 6.67 xx 10^(-11) Nm^(2)//kg^(2))

    The acceleration due to gravity at the moon's surface is 1.67 ms^(-2) . If the radius of the moon is 1.74 xx 10^(6) m , calculate the mass of the moon.

    Mass of moon is 7.3 xx 10^(22) kg and its radius is 1.74 xx 10^(6) m. Find the value of the acceleration due to gravity on the moon.

    Taking the mass of earth equal to 6 xx 10^(24) kg and its radius equal to 6.4 xx 10^6 m, calculate the value of acceleration due to gravity at a height of 2000 km above the earth surface. Take G = 6.7xx10^(-11) N m^(2) kg^(-2)

    The acceleration due to gravity at the moon's srface is 1.67 ms^(-2) . If the radius of the moon is 1.74 xx 10^(6) m , calculate the mass of the moon. Use the known value of G.

    Find the distance of a point from the earth's centre where the resultant gravitational field due to the earth and the moon is zero. The mass of the earth is 6.0xx10^24 kg and that of the moon is 7.4x10^22 kg. The distance between the earth and the moon is 4.0xx10^5km .

    Home
    Profile