Which of the statements about the reaction below are incorrect?
`2PbO(s) + C(s) rarr 2Pb(s) + CO_(2)(g)`
(a) Lead is getting reduced.
(b) Carbon dioxide is getting oxidised.
(c) Carbon is getting oxidised.
(d) Lead oxide is getting reduced.

Options

A. (a) and (b)
B. (a) and (c)
C. (a), (b) and (c)
D. all

Explanation

To determine which of the statements about the reaction `2PbO(s) + C(s) → 2Pb(s) + CO₂(g)` are incorrect, we need to analyze the oxidation states of the elements involved in the reaction.

### Step-by-Step Solution:

1. **Identify the Reactants and Products**:
- Reactants: Lead(II) oxide (PbO) and Carbon (C)
- Products: Lead (Pb) and Carbon dioxide (CO₂)

2. **Determine the Oxidation States**:
- For Lead(II) oxide (PbO):
- The oxidation state of lead (Pb) in PbO is +2 (since O is -2, and the compound is neutral).
- For Lead (Pb) in its elemental form:
- The oxidation state of Pb is 0.
- For Carbon (C) in its elemental form:
- The oxidation state of C is 0.
- For Carbon dioxide (CO₂):
- The oxidation state of carbon (C) in CO₂ is +4 (since O is -2, and there are two O atoms).

3. **Analyze Changes in Oxidation States**:
- Lead (Pb) changes from +2 in PbO to 0 in Pb, indicating a reduction (decrease in oxidation state).
- Carbon (C) changes from 0 to +4 in CO₂, indicating oxidation (increase in oxidation state).

4. **Evaluate Each Statement**:
- (a) Lead is getting reduced.
- **Incorrect**: It is lead oxide (PbO) that is being reduced, not lead itself.
- (b) Carbon dioxide is getting oxidised.
- **Incorrect**: Carbon dioxide is not being oxidized; carbon is being oxidized to form CO₂.
- (c) Carbon is getting oxidised.
- **Correct**: Carbon is indeed getting oxidized from 0 to +4.
- (d) Lead oxide is getting reduced.
- **Correct**: Lead oxide (PbO) is being reduced to lead (Pb).

5. **Conclusion**:
- The incorrect statements are (a) and (b).
- The correct statements are (c) and (d).

### Summary of Incorrect Statements:
- (a) Lead is getting reduced. (Incorrect)
- (b) Carbon dioxide is getting oxidised. (Incorrect)