10 mL of a solution of NaOH is found to be completely neutralised by 8 mL of a given solution of HCl. If we take 20 mL of the same solution of NaOH, the amount HCl solution (the same solution as before) required to neutralise it will be

Options

A. 4 mL
B. 8 mL
C. 12 mL
D. 16 mL

Explanation

To solve the problem, we need to determine how much HCl solution is required to neutralize 20 mL of NaOH solution, given that 10 mL of NaOH is neutralized by 8 mL of HCl.

### Step-by-Step Solution:

1. **Understand the Neutralization Reaction**:
The neutralization reaction between NaOH (a base) and HCl (an acid) can be represented as:
\[
\text{NaOH} + \text{HCl} \rightarrow \text{NaCl} + \text{H}_2\text{O}
...