Theorem 7.7 : In any triangle, the side opposite to the larger (greater) angle is longer
Text Solution
AI Generated Solution
To prove that in any triangle, the side opposite to the larger angle is longer, we can follow these steps:
### Step 1: Consider Triangle ABC
Let triangle ABC be given, where we know that angle C is greater than angle B (∠C > ∠B).
### Step 2: Assume the Opposite
Assume for contradiction that the side opposite to angle C (which is side AB) is not longer than the side opposite to angle B (which is side AC). This means we assume that side AC is greater than or equal to side AB (AC ≥ AB).
...
Topper's Solved these Questions
NCERT THEOREMS
NCERT ENGLISH|Exercise THEOREM 7.8|1 Videos
NCERT THEOREMS
NCERT ENGLISH|Exercise THEOREM 8.1|1 Videos
NCERT THEOREMS
NCERT ENGLISH|Exercise THEOREM 7.6|1 Videos
LINES AND ANGLES
NCERT ENGLISH|Exercise Exercise 6.1|6 Videos
NUMBER SYSTEMS
NCERT ENGLISH|Exercise EXERCISE 1.4|2 Videos
Similar Questions
Explore conceptually related problems
Theorem 7.6 : If two sides of a triangle are unequal, the angle opposite to the longer side is larger (or greater)
Theorem 7.3 : The sides opposite to equal angles of a triangle are equal.
If the area (!) and an angle (theta) of a triangle are given , when the side opposite to the given angle is minimum , then the length of the remaining two sides are
If the angle opf a triangle are in the ratio 1:2:3, then show that the sides opposite to the respective angle are in the ratio 1: sqrt3:2.
When any two sides and one of the opposite acute angle are given, under certain additional conditions two triangles are possible. The case when two triangles are possible is called the ambiguous case. In fact when any two sides and the angle opposite to one of them are given either no triangle is posible or only one triangle is possible or two triangles are possible. In the ambiguous case, let a,b and angle A are given and c_(1), c_(2) are two values of the third side c. On the basis of above information, answer the following questions Two different triangles are possible when
Theorem 6.5 : If one angle of a triangle is equal to one angle of the other triangle and the sides including these angles are proportional, then the two triangles are similar.
Prove that in a triangle, other than an equilateral triangle, angle opposite the longest side is greater than 2/3 of a right angle.
In a triangle the greater angle has the longer side opposite to it.
If the bisector of an angle of a triangle bisects the opposite side, prove that the triangle is isosceles.
In the given triangle, name the following: (a). The vertices of the triangle (b). The sides of the triangle (c) the side opposite to vertex Q (d) the vertex opposite to side PQ (e) the three angles using three letters (f) the three angles using a single letter