Prove that two triangles having the same base and equal areas lie between the same parallels.
Text Solution
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Since `CEbotAB` and `DFbotAB`
Since, lines are perpendicular to same line are parallel to each other.
`CE||DF`
Now,
`ar(ABC)=1/2xxbb"Base"xxBB'Height"`
`ar(ABC)=1/2xxABxxCE`
Similarly,
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