Chords of a circle which are equidistant from the centre are equal.
Text Solution
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In `/_\AOX` and `/_\DOY`
`/_OXA=/_OYD` (perpendicular angles)
`OA=OD` (radius)
`OX=OY` (given)
By RHS congruency, `/_\AOX` and `/_\DOY` are congreunt.
`AX=DY` (CPCT)
For chord `AB`
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