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Draw a triangle A B C with side B C=7c...

Draw a triangle `A B C` with side `B C=7c m` , `/_B=45^circ` , `/_A=105^circ` . Then construct a triangle whose sides are `(4//3)` times the corresponding sides of ` A B C` .

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In order to construct `△ABC, `we follow the following steps :
STEP I Draw `BC=7 cm.`
STEP II At B construct `∠CBX=45^@` and at C construct `∠BCY=180^@−(45^@−105^@ )=30^@` ...
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