A doubly ionised Li atom is excited from its ground state(n = 1) to n = 3 state. The wavelengths of the spectral lines are given by `lamda_(32), lamda_(31)` and `lamda_(21)`. The ratio `l_(32)//lamda_(31)` and `l_(21)//l_(31)` are, respectively

Electrons in H_2 atom are excited from n = 1 (ground state) to n = 4 state. The number of spectral lines observed are

Hydrogen atom is in its n^(th) energy state. If de-Broglie wavelength of the electrons is lamda , then

Hydrogen H, deuterium D, singlyionized helium He^(+) and doubly ionized lithium L^(++) all have one electron around the nucleus. Consider n=2 and n=1 transition. Thewavelengths ofthe emitted radiations are lamda_(1),lamda_(2),lamda_(3) and lamda_(4) respectively. Then approximately:

The wavelength of the first Lyman lines of hydrogen He^(+) and Li^(2+) ions and lamda_(1),lamda_(2)& lamda_(3) the ratio of these wavelengths is

The wavelength of the first Lyman lines of hydrogen He^(+) and Li^(2+) ions and lamda_(1),lamda_(2)& lamda_(3) the ratio of these wavelengths is

Hydrogen (""_(1)H^(1)) , Deuterium (""_(1)H^(2)) , single ionised Helium (""_(2)He^(4))^(+) and doubly ionised lithium (""_(3)Li^(6))^(++) all have one electron around the nucleus. Consider an electron transition from n=2 to n=1. If the wavelength of emitted radiation are lamda_(1),lamda_(2),lamda_(3) and lamda_(4) respectively then approximately which one of the following is corrent ?