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(sin2A+sin2B+sin2C)/(sinA+sinB+sinC)=8si...

`(sin2A+sin2B+sin2C)/(sinA+sinB+sinC)=8sin(A/2)sin(B/2)sin(C/2)`

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(sin2A+sin2B+sin2C)/(sinA+sinB+sinC)i se q u a lto 8sin(A/2)sin(B/2)sin(C/2) (b) 8cos(A/2)cos(B/2)cos(C/2) 8tan(A/2)tan(B/2)tan(C/2) (d) 8cot(A/2B)/2cot(C/2)

(sin2A+sin2B+sin2C)/(sinA+sinB+sinC)i se q u a lto 8sin(A/2)sin(B/2)sin(C/2) (b) 8cos(A/2)cos(B/2)cos(C/2) 8tan(A/2)tan(B/2)tan(C/2) (d) 8cot(A/2B)/2cot(C/2)

(sin2A+sin2B+sin2C)/(sinA+sinB +sinC) is equal to

(sin2A+sin2B+sin2C)/(sinA+sinB +sinC) is equal to