The last member of Lymann series of Hydrogen atom is `912Å` Calculate The wavelength of series limit of blamer series.

If the wavelength of the first member of Blmer series of hydrogen spectrum is 6563Å A, then the wavelength of second member of Blamer series will be

The short wavelength limit for the Lyman series of the hydrogen spectrum is 913.4 Å. Calculate the short wavelength limit for Balmer series of the hydrogen spectrum.

If the wavelength of the first member of Balmer series of hydrogen spectrum is 6563Å , then the wavelength of second member of Balmer series will be

If the wavelength of the first member of Balmer series in hydrogen spectrum is 6563 Å, calculate the wavelength of the first member of Lymen series in the same spectrum.

The wavelength of the first member of Lyman series is 1216 Å . Calculate the wavelength of second member of Balmer series.

If the shortest wavelength of Lyman series of hydrogen atom is x, then the wavelength of first member of Balmer series of hydrogen atom will be

If the wavelength of series limit of Lyman series for He^(+) ion is x Å, then what will be the wavelength of series limit of Balmer series for Li^(2+) ion?

If the wavelength of series limit of Lyman series for He^(+) ion is x Å, then what will be the wavelength of series limit of Balmer series for Li^(2+) ion?

The short weve length limit for the Lyman series of the hydrogen spectrum is 913.4 Å Calculate the short wevelength limit for Balmer series of the hydrogen spectrum.