M is `a` fixed wedge. Masses `m_(1)` and `m_(2)` are connected by `a` light string. The wedge is smooth and the pulley is smooth and fixed `m_(1)=10kg` and `m_(1)=7.5kg` . When `m_(2)` is just released, the distance it will travel in 2 second is.

Two masses m_(1) and m_(2) are connected by a light string passing over a smooth pulley. When set free m_(1) moves downward by 2 m in 2 s. The ratio m_(1)//m_(2) is

Two masses m_(1) and m_(2) are attached to a string which passes over a frictionless smooth pulley. When m_(1)=10kg,m_(2)=6kg , the acceleration of masses is

[" Two masses "m_(1)" and "m_(2)" are "],[" connected by means of a "],[" light string,that passes over "],[" a light pulley as shown in the "],[" figure.If "m_(1)=2kg" and "m_(2)=],[5kg" and a vertical force "F" is "],[" applied on the pulley then "],[" find the accelerations of the "],[" masses and that of the "],[" pulley when the force is "],[F=70N]

In the figure, pulleys are smooth and strings are massless, m_(1) =1 kg and m_(2)=(1)/(3) kg. To keep m_(3) at rest, mass m_(3) should be

Find the acceleration of masses m_(1) and m_(2) moving down the smooth incline plane. The string and the pulley are masseless and frictionless.

Two blocks of masses m_(1) = 3 kg and m_(2) = (1)/(sqrt3) kg are connected by a light inextensible string which passes over a smooth peg . The blocks rest on the inclined smooth planes of a wedge and the peg is fixed to the top of the wedge . The planes of the wedge supporting m_(1) and m_(2) are inclined at 30^(@) and 60^(@) respectively , with the horizontal. Calculate the acceleration of masses and the tension in the string .

Two bodies of masses m_(1) and m_(2) (m_(2) gt m_(1)) are connected by a light inextensible string which passes through a smooth fixed pulley. The instantaneous power delivered by an external agent to pull m_(1) with constant velocity v is :