A charge having q/m equal to `10^(g)` c/kg and with velocity `3 xx 10^(5)` m/s enters into a uniform magnetic field B = 0.3 tesla at an angle `30^(@)` with direction of field. Then radius of curvature will be:

A charge having q/m equal to 10^(8) c/kg and with velocity 3 xx 10^(5) m/s enters into a uniform magnetic field B = 0.3 tesla at an angle 30^(@) with direction of field. Then radius of curvature will be:

A proton moving with a velocity 3xx10^(5)m//s enters a magnetic field of 0.3 tesla at angle of 30^@ with the field. The radius of curvature of its path will be (e/m for proton =10^(8)C//kg )

A beam of protons with a velocity 4 xx 10^(5) m/sec enters a uniform magnetic field of 0.3 Testa at an angle of 60^(@) to the magnetic field. Find the radius of the helical path taken by the proton beam. Also find the pitch of the helix, which is the distance travelled by a proton in the beam parallel to the magnetic field during one period of rotation [Mass of proton = 1.67 xx 10^(-27) kg. charge on proton = 1.6 xx 10^(19)C ]

A beam of protons with a velocity of 4 xx 10 ^5 ms^(-1) enters a uniform magnetic field of 0.3 T. The velocity makes an angle of 60^@ with the magnetic field. Find the radius of the helicla path taken by the proton beam and the pitch of the helix. Given that mass of proton = 1.67 xx 10^-27kg

A beam of protons moving with a velocity of 4 xx 10^(5) m/s enters a uniform magnetic field of 0.3 T at an angle of 60◦ with the magnetic field. What is the radius of the helical path described by the proton beam? [m_p=1.67 xx 10^(-27) kg and the charge on the proton =1.6 xx 10^(-19) C]

A proton moving with velocity (10^7) m/s to enters a magnetic field of 1.5 T making an angle 30° with the direction of the field. Find the radius of the helical path and its frequency of rotational motion

A proton moving with a velocity 2 . 5 xx 10^(7) m-s ^(-1) , enters a magnetic field of intensity 2.5 T at an angle 30^(@) with the magnetic field. The force on the proton is

A proton moving withh a velocity 2.5xx10^(7)m//s enters a magnetic field of intensity 2.5T making an angle 30^(@) with the magnetic field. The force on the proton is