Keeping coordinate axes parallel, the origin is shifted to a point (1, –2), then transformed equation of `x^2 + y^2 = 2` is -

When the origin is shifted to the point (2 , 3) the transformed equation of a curve is x^(2) + 3xy - 2y^(2) + 17 x - 7y - 11 = 0 . Find the original equation of curve.

If the origin is shifted to the point (2,-2), the equation to which the equation (x-2)^(2) + (y+2)^(2)=9 transformed is

Find the transformed equations of the following when the origin is shifted to the point (1, 1) by a translation of axes : x^2-y^2 - 2x+ 2y = 0 .

If origin is shifted to the point (a,b) then what will be the transformed equation of the curve (x-a)^(2)+(y-b)^(2)=r^(2) ?

If origin is shifted to the point (a,b) then what will be the transformed equation of the curve (x-a)^(2)+(y-b)^(2)=r^(2) ?