Planck's constant (h) and de Broglie wavelength `(lambda)` are related through the equation `h=lambdasqrt(2mE)`, where 'm' and 'E' denote the mass and kinetic energy respectively of the moving particle. The dimensional formula of h is given by

The de Broglie wavelength (lambda) of a particle is related to its kinetic energy E as

The de-Broglie wavelength lambda . of a particle isrelated to its kinetic energy E_K as

Show.that the de-Broglie wavelength lambda of electrons of energy E is given by the relation, lambda = h/sqrt(2mE) .

Dual nature of matter was proposed by de Broglie in 1923, it was experimentally verified by Davisson and Germer by diffraction experiment. Wave haracter of matter has significance only for microscopic particles. De Broglie wavelength (lambda) can be calculated using the relation, (lambda) = (h)/(m v) where 'm' and 'v' are the mass and velocity of the particle. Planck's constant has same dimension as that of

Show that the do Broglie wavelength lamda of an electron of energy E is given by the relation lamda = =h/(sqrt2mE)

Show that the de-Broglie wavelength lambda of electrons of energy E is givne by the relation: lambda= h /(sqrt(2 m E)) .

If the kinetic energy of a moving particle is E , then the de-Broglie wavelength is

If the kinetic energy of a moving particle is E , then the de-Broglie wavelength is