`log_4 2-log_8 2+log_16 2-.....oo`

The sum of the series log_(4)2-log_(8)2+log_(16)2-.... is

-log_8 log_4 log_2 16=

Prove that log_(4)2-log_(8)2+log_(6)2..."is"1-log_(e)2.

The sum of the series "log"_(4)2-"log"_(8)2 + "log"_(16)2- "log"_(32) 2+…., is

The sum of the series "log"_(4)2-"log"_(8)2 + "log"_(16)2- "log"_(32) 2+…., is

Evaluate log_2 log_2 16

Solve for x, y , z . log_2 x + log_4 y + log_4 z =2 log_3 y + log_9 z + log_9 x =2 log_4 z + log_16 x + log_16 y =2

Find x, if : 2 + log x = log 45 - log 2 + log 16 - 2 log 3.