The efficiency of a Carnot cycle is `1//6`. By lowering the temperature of sink by `65 K`, it increases to `1//3`. The initial and final temperature of the sink are

The efficiency of an ideal engine is 1/8 . By lowering the temperature of the sink by 100 K, it increases to 1/4 . Find initial and final temperature of sink.

The efficiency of a Carnot cycle is 1/6 . If on reducing the temperature of the sink by 65^@C , the efficiency becomes 1/3 , find the initial and final temperatures between which the cycle is working.

The efficiency of a carnot cycle is 1/6. If on reducing the temperature of the sink by 65^@C , the efficiency becomes 1/3. If final temperature of the sink is N times 65K then .N. is equal to

The efficiency of a carnot cycle is 1/8 On decreasing the temperature of the sink by 65^(@) C, the efficiency increases to 1/3 . Calculate the temperature of source (in C^(@)

The efficiency of a Carnot cycle is 1//6 . If on reducing the temperature of the sink by 65^@C , the efficiency becomes 1//3 , find the source and sink temperatures between which the cycle is working.

The efficiency of a Carnot cycle is 1//6 . If on reducing the temperature of the sink by 65^@C , the efficiency becomes 1//3 , find the source and sink temperatures between which the cycle is working.

The efficiency of a carnot cycle is 1//6 . On decreasing the tempertaure of the sink by 65^(@)C , the efficiency increases to 1//3 .Calculate the tempretaure of source and sink .

Thermodynamics deals with the concept of heat and the exchange of heat energy. The efficiency of a Carnot engine is 1/6 .If on reducing the temperature of sink by 65°C .Its efficiency becomes 1/3 .Find the temperature of the sink and the source.