lim_(theta rarr0)(sin theta/4)/(theta)

Using lim_(theta rarr0)(sin theta)/(theta)-1 prove that the area of circle of radius R is pi R^(2) (Figure)

lim_(theta rarr0)[(12sin theta)/(theta)]+[(13tan theta)/(theta)]=k where [^(*)] denotes greatest integer,then [(k)/(5)] is equal to:

Given that lim_(theta rarr 0) (sin theta)/theta = 1 and lim_(theta rarr 0) cos theta = 1 Evaluate lim_(theta rarr 0) (tan theta)/theta

Given that lim_(theta rarr 0) (sin theta)/theta = 1 and lim_(theta rarr 0) cos theta = 1 Evaluate lim_(theta rarr pi/2) (cot theta)/(pi/2 - theta)

lim_(theta rarr 0) (1-cos theta)/(theta. costheta)=

Evaluate the following : lim_(theta rarr 0)(sin4 theta)/(tan3 theta) .

lim_(theta rarr 0) (1-cos theta)/(theta sin theta) =

lim_(theta rarr0)((sin theta)/(sin((theta)/(2))))=2