On the perpendicular bisector of an electric dipole, electric intensity E and potential V are

The direction of the intensity of the electric field at a point on the perpendicular bisector of an electric dipole ( vec(p) = electric dipole moment ) is

A point Q lies on the perpendicular bisector of an electric dipole of dipole moment P. If the distance of Q from the dipole is r, then electric field at Q is proportional to

A point Q lies on the perpendicular bisector of an electrical dipole of dipole moment p, If the distance of Q from the dipole is r (much larger than the size of the dipole), then electric field at Q is proportional to

Determine the electric field intensity at a point on the perpendicular bisector of an electric dipole. If the dipole is very small, how will the field intensity be modified ?

A and B are two points on the axis and the perpendicular bisector of an electric dipole. A and B are far away from the dipole and at equal distances from it. The potentials at A and B are V_(A) and V_(B) respectively. Then

A test charge q_(0) is brought from infinity along the perpendicular bisector of an electric dipole. The work done on q_(0) by the electric field of the dipole is

A point Q lies on the perpendicular bisector of an electrical dipole of dipole moment p , If the distance of Q from the dipole is r (much larger than the size of the dipole), then electric field at Q is proportional to