[" A body of mass "1.0kg" is falling with an "],[" acceleration of "102m/sec." Its apparent "],[" weight will be "(10/sec)2g=m]

A body of mass 1.0 kg is falling with an acceleration of 10 m//s^(2) . Its apparent weight will be (g=10m//sec^(2))

A man of weight 80 kg is standing in an elevator which is moving with an acceleration of 6m//s^(2) in upward direction. The apparent weight of the man will be (g=10m//s^(2))

A man of weight 80 kg is standing in an elevator which is moving with an acceleration of 6m//s^(2) in upward direction. The apparent weight of the man will be (g=10m//s^(2))

A body of mass 8 kg is hanging from another body of mass 12 kg. The combination is being pulled up by a string with an acceleration of 2.2 m/sec2. The tension T1 will be -

A man of mass 75 kg is standing in an elevator which is moving with an acceleration of 5 m//s^2 in upward direction.The apparent weight of the man will be (g=10 m//s^2)

Mass of a person sitting in a lift is 50 kg . If lift is coming down with a constant acceleration of 10 m//sec^(2) . Then the reading of spring balance will be (g=10m//sec^(2))

A body of mass 10 kg is moving with a velocity 10/sec. When a force is applied on it, after 25 seconds its velocity become 30m/sec. Find the magnitude of the force applied.

5A body of mass 15 kg moving with a velocity of 10 m//s is to be stopped by a resistive force in 15 sec, the force will be -

A man of mass 80 kg stands in an elevator. Calculate his apparent weight when, (iv) the elevator cable breaks (g = 10 m//s^2)