[" 1."y^(4)-3y^(2)+2y+1" से "y-1" ये भाथ देने पर शेषफल होगा "],[[" (i) "1," (ii) "4," (iii) "3]]

(y + 1) (2y-1) - (3y-1) (y + 2)

The focus of the parabola y^(2) - x - 2y + 2 = 0 is (i) ((5)/( 4), 1) (ii) ((1)/(4),1) (iii) ((3)/(4),1) (iv) (1,1)

Simplify (2y -1) (4y - 3)

{:(,"Hyperbola point ",,"Centre"),(I,4(x+3) ^(2) -9(y-2)^(2) =36",", ,(a) ("2,-1")),(II,3(x-3) ^(2) -4(y-1)^(2) =12",",,(b) ("-3,2")),(III,9(x-2) ^(2) (2) -5(y-1) ^(2) = 45"," ,,(c) (2,1)) ,(IV,x^(2) -4x-y^(2) -2y -8=0",",,(d) ("3,1")):}

If p(y)=4+3y-y^(2)+5y^(3) , find (i) p (0) , (ii) p(2) , (iii) p(-1) .

From the curve y= |x| , draw (i) y= |x-1| + 1 """" (ii) y= |x+1|-1 """ (iii) y=|x+2|+3

If p(y)=y^(3)+y^(2)+y+1 find : (i) y(1) (ii) y(-1)

If p(y)=y^(3)+y^(2)+y+1 find : (i) y(1) (ii) y(-1)

I. y^(2) + y - 1 = 4 - 2y - y^(2) II. x^(2)/2 - 3/2 x = x - 3