sec(tan sqrt(x))^(oo T)" Gapet "pi

tan x sqrt( sec x )

Find derivative of sec (tan(sqrt(x))) w.r.t.to x

tan x+sec x=sqrt(3)

If y= sec ( tan sqrt x ) ,then (dy)/(dx) =

If y=sqrt(tan x+sqrt(tan x +sqrt(tan x+....oo))) " then prove that " dy/dx = sec^2 x /(2y-1).

If y=sqrt(tan x+sqrt(tan x +sqrt(tan x+....oo))) " then prove that " dy/dx = sec^2 x /(2y-1).

If 0lt=xlt=pi/3 then range of f(x)=sec(pi/6-x)+sec(pi/6+x) is (a) (4/(sqrt(3)),oo) (b) (4/(sqrt(3)),oo) (c) (0,4/(sqrt(3))) (d) (0,4/(sqrt(3)))

If y=sqrt(tan x+sqrt(tan x+sqrt(tan x+...+oo))) then prove that (2y-1)(dy)/(dx)-sec^(2)x=0