[" Find the equation of the circle whose radius is "3" and which touches internally the circle "],[x^(2)+y^(2)-4x-6y-12=0" at the point "(-1,-1)]

The equation to the circle whose radius is 3 and which touches internally the circle x^(2)+y^(2)-4x+6y-12=0" at this point (-1,1) is"

Centre of the circle whose radius is 3 and which touches internally the circle x^(2)+y^(2)-4x-6y-12=0 at the point (-1 -1) is

Centre of the circle whose radius is 3 and which touches internally the circle x^(2)+y^(2)-4x-6y-12=0 at the point (-1 -1) is

Centre of the circle whose radius is 3 and which touches internally the circle x^(2)+y^(2)-4x-6y-12=0 at the point (-1 -1) is

Centre of the circle whose radius is 3 and which touches internally the circle x^(2)+y^(2)-4x-6y-12=0 at the point (-1 -1) is

Find the equation of the circle whose radius is 5 and which touches the circle x^(2)+y^(2)-2x-4y-20=0 externally at the point (5,5).

Solve the following:Find the co-ordinates of centre of the circle whose radius is 3 units and which touches internally to the circle x^2+y^2-4x-6y-12=0 at point (-1,-1).