A stone projected vertically upward moves according to the law s = `100t-16t^2`. The maximum height reached is

A stone projected vertically upward moves according to the law s=100t-16t^2 . The acceleration at t=2 sec is

A stone projected vertically upward moves according to the law s=48t-16t^2 . The time taken by the stone to reach the point of projection is

A stone thrown vertically upwards rises S ft in t seconds where S =112t-16t ^(2) . The maximum height reached by the stone is

A missile is fired from the ground level rises x metres vertically upwards in t second, where x=100 t-25/2t^(2) . The maximum height reached is

A missile is fired from the ground level rises x metre vertically upwards in t second, where x=100t-(25)/(2)t^(2) . The maximum height reached is

A ball is thrown vertically upwards, moves according to the law s=13.8t-4.9t^(2) where s is in metres and t is in seconds. (i) Find the acceleration at t = 1 (ii) Find velocity at t = 1 (iii) Find the maximum height reached by the ball?

A missile fixed from ground level raises x metres vertically upwards in t seconds and x = 100t - (25)/(2) t^(2) . Find The maximum height reached

A body projected vertically upwards with a velocity of 19.6 m//s reaches a height of 19.8 m on earth. If it is projected vertically up with the same velocity on moon, then the maximum height reached by it is

A stone thrown vertically upwards satisfies the equations s = 80t –16t^(2) . The time required to reach the maximum height is