[" (3) Subteact "2.6times10^(4)" beom "3...

[" (3) Subteact "2.6times10^(4)" beom "3.9times10^(5)" With due eegad to Sigititant figues "],[(9)3*64times10^(5)" (b) "3.7times10^(5)quad " (c) "3.6times10^(5)quad " (d) "3.65times10^(6)]

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Substract 3.2 xx 10^(-6) from 4.7 xx 10^(-4) with due regard to significant figures.

If 2.6times10^(-6) is added to 3.2times10^(-5) with due regard to significant figures,then the result will be

(3^(5)times10^(5)times9)/((90)^(2))

Simplify: 10^(-1)times10^(2)times10^(-3)times10^(4)times10^(-5)times10^(6)

(3^(-5)times10^(-5)times125)/(5^(-7)times6^(-5))

" (f) (5^(6)times a^(7))/(5^(2)times a^(3)times(10)^(0))

3^(-5)times10^(-4)times(5^(4))/(5^(2))times6^(-5)=

Human genome is said to have approximately (a) 3 xx 10 ^(9) bp (b) 3 xx 10^(6) bp (c) 6.6 xx 10^(6) bp (d) 3.3 xx 10^(6) bp