" (ii) "(1+y^(2))dx=(tan^(-1)y-x)dy

Solve the following differential equations (i) (1+y^(2))dx = (tan^(-1)y - x)dy (ii) (x+2y^(3))(dy)/(dx) = y (x-(1)/(y))(dy)/(dx) + y^(2) = 0 (iv) (dy)/(dx)(x^(2)y^(3)+xy) = 1

Solve : (1+y^(2))dx=(tan^(-1)y-x)dy , given that y=0 when x = -1.

The I.E. of (1+y^(2))dx=(tan^(-1)y-x)dy is ___________.

The integrating factor of (1+y^(2)) dx = (tan^(-1)y-x) dy is -

The general solution of the differential equation (1 + y^(2)) dx = (tan ^(-1) y-x)dy is

The integrating factor of (1+y^(2)) dx = (tan^(-1)y-x) dy is -

Solve the following differential equation: (1+y^(2))dx=(tan^(-1)y-x)dy

The integrating factor of (1+y^(2)) dx = (tan^(-1)y-x) dy is -