[" Two parallel chords of a circle of radius unity which "],[" are on the same side of the centre subtend angles "],[72^(@)" and "144^(@)" at the centre.The distance between "],[" the chords is "]

Let PQ and RS be two parallel chords of a given circle of radius 6 cm, lying on the same side of the center. If the chords subtends angles of 72^(@) and 144^(@) at the center and the distance between the chords is d, then d^(2) is equal to

Two parallel chords of a circle,which are on the same side of centre,subtend angles of 72^(@) and 144^(@) respetively at the centre Prove that the perpendicular distance between the chords is half the radius of the circle.

AB and CD are two parallel chords of a circle of radius 6 cm lying on the same side of the centre. If the chords subtend angles of 72^circ and 144^circ at the centre, find the distance between the chords.

Two parallel chords of a circle, which are on the same side of centre,subtend angles of 72^@ and 144^@ respetively at the centre Prove that the perpendicular distance between the chords is half the radius of the circle.

Two parallel chords of a circle , 12 cm and 16 cm long are on the same of the centre. The distance between them is 2 cm. Find the radius of the circle.

Two parallel chords of a circle , 12 cm and 16 cm long are on the same of the centre. The distance between them is 2 cm. Find the radius of the circle.

Two parallel chords of a circle, of diameter 20 cm lying on the opposite sides of the centre are of lengths 12 cm and 16 cm . The distance between the chords is

Two parallel chords are drawn on the same side of the centre of a circle of radius R .It is fouind that they subtend angles of theta and 2 theta at the centre of the circle.The prependicular distance between the chords is