A projectile is thrown at angle `theta ` and` (90^(@) -theta )` from the same point with same velocity `98 m//s`. The heights attained by them, if the difference of heights is 50 m will be`- ("in" m) `

Two bodies are thrown at angles theta and (90- theta ) from the same point with same velocity 25ms^(-1) . If the difference between their maximum heights is 15m, the respective maximum heights are (g=10 ms^(-2) )

Two bodies are thrown at angles theta and (90- theta ) from the same point with same velocity 25ms^(-1) . If the difference between their maximum heights is 15m, the respective maximum heights are (g=10 ms^(-2) )

A body is thrown upwards with a velocity 9.8 m/s what shall be the height attained by it?

Show that for angles of projection theta and 90^(@)-theta , the range of the projectile is the same.

A projectile is thrown at an angle of theta=45^(@) to the horizontal, reaches maximum reaches a maxium height of 16m , then

If a body is thrown up with the velocity of 15 m/s then maximum height attained by the body is (g = 10m//s)