" Solve "(1)/((a+b+x))=(1)/(a)+(1)/(b)+(1)/(x)," where "a+b!=0

Solve (1)/(a+b+x)=(1)/(a)+(1)/(b)+(1)/(x),a+b!=0

Solve for: (1)/(2a+b+2x)=(1)/(2a)+(1)/(b)+(1)/(2x)

Solve for 'x' : (1)/(a+b+x)=(1)/(a)+(1)/(b)+(1)/(x) " " a != 0, b!=0, x !=0

Solve: (1)/((a+b+x))=(1)/(a)+(1)/(b)+(1)/(x),[xne0,xne-(a+b)].

Solve for x : (1)/(a + b + x) = (1)/(a) + (1)/(b) + (1)/(x) , a ne b ne 0 , x ne 0 , x ne -(a + b)

Solve the following quadratic equation by factorization method (1)/(a+b+x)=(1)/(a)+(1)/(b)+(1)/(x),a+b!=0

Solve the following quadratic equations by factorization methd: (1)/(a+b+x)=(1)/(a)+(1)/(b)+(1)/(x),a+b!=0

Solve the equations : (1)/(a+b-x)=(1)/(a)+(1)/(b)-(1)/(x)

Solve x^(2)+((a+b)/(a)+(a)/(a+b))x+1=0

Long-answer type questions (L.A.) (1)/(a+b+x)=(1)/(a)+(1)/(b)+(1)/(x){xne0,-(a+b)}