A `p-n` junction diode has breakdown voltage of `28V`. If applied external in reverse bias is `40 V` the current through it is

If a p-n junction diode is in reversed bias

In the figure, the reverse breakdown voltage of a Zener diode is 5.6V, then the current I_(Z) through the diode is

In the figure, the reverse breakdown voltage of a Zener diode is 5.6V, then the current I_(Z) through the diode is

The reverse breakdown voltage of a Zener diode is 5.6V in the given circuit. The current I_(2) through the Zener is:

A zener diode has break down voltage of 5.0 V. The resistance required to allow a current of 100 mA through the zener in reverse bias when connected to a battery of emf 12V is

A zener diode having breakdown voltage 5.6 V is connected in reverse bias with a battery of emf 10 V and a resistance of 100 Omega in series . The current flowing through the zener is.

A Zener diode of breakdown voltage "10V" is used as a voltage regulator as shown in the figure. The current through the Zener diode is:

A p-n junction diode has a forward bias resistance of 10 Omega and a reverse bias resistance of 10 k Omega . It is connected in series with a resistance of 990 Omega and a.d.c. source of 5V in such a way that the negative terminal of the source is connected to then region of the p-n junction. What is the current flowing in the circuit?

A zener diode has a breakdown voltage of 10 V and is used in a voltage regulator circuit as shown in the given figure what will be current through the diode

In the circuit below ,the breakdown voltage of zener diode is 10v. The current through diode would be