A toroid has an iron core with an internal magnetic field of `10 pi mT`, when the current in the winding of 1500 turns per meter is 10 A. Determing the field due to magnetisation `(mu = 4pi xx 10^(-7) Hm ^(-1))`

The strength of the magnetic field along solenoid having 5000 turns per meter is 3.14 xx 10^-2 T . The current flowing through the solenoid is

A long straight wire is carrying a current of 12 A . The magnetic field at a distance of 8 cm is (mu_(0) =4pi xx 10^(-7) N A ^(2))

A long straight wire is carrying a current of 12 A . The magnetic field at a distance of 8 cm is (mu_(0) =4pi xx 10^(-7) N A ^(2))

The magnetic field at the centre of a circular current carrying loop of radius 12.3 cm is 6.4 xx 10^-6T . What will be the magnetic moment of the loop? (mu_0 = 4pi xx 10^-7 TmA^-1)

A toroid has a non-ferromagnetic core of inner radius 20.5 cm and outer radius 21.5 cm, around which 4200 turns of a wire are wound. If the current in the wire is 10 A, the magnetic field inside the core of the toroid is (mu_(0)=4pi times 10^(-7)Hm^(-1))

Find the magnitude of the magnetic field at the center of an equilateral triangular loop of side length 1m which is carrying a current of 10A. ( Take mu_(0) = 4pi xx 10^(-7) NA^(-2))

Find the magnitude of the magnetic field at the center of an equilateral triangular loop of side length 1m which is carrying a current of 10A. ( Take mu_(0) = 4pi xx 10^(-7) NA^(-2))

A toroid has a core of inner radius 20cm and outer radius 22cm around which 4200 turns of a wire are wound. If the current in the wire is 10A, what is the magnetic field outside the toroid.