इन समीकरण को हल कीजिये `2sin^(2) theta+sin^(2) 2theta=2`

2sin^(2)theta+sin^(2)2 theta=2

Solve: 2sin^(2)theta+sin^(2)2theta=2

Solve: 2sin^(2)theta+sin^(2)2theta=2

Solve: 2sin^(2)theta+sin^(2)2theta=2

sin2 theta=2sin theta cos theta

The value of the expression (cos^(6)theta + sin^(6) theta – 1) (tan^(2) theta + cot^(2) theta + 2) is: समीकरण (cos^(6)theta + sin^(6) theta – 1) (tan^(2) theta + cot^(2) theta + 2) का मान है:

If 2sin theta=2-cos theta find sin theta

Prove each of the following identities : (sin theta + cos theta)/(sin theta - cos theta) + (sin theta - cos theta)/(sin theta + cos theta) = (2) /((sin^(2) theta - cos^(2) theta)) = (2) /((2sin^(2) theta -1))

Complete the following activity by filling the boxes. sin^(2) theta+cos^(2) =square ….(Identity) Dividing each term by sin^(2) theta , we get (sin^(2)theta)/(sin^(2) theta)+(cos^(2)theta)/(sin^(2)theta)=(square)/(sin^(2)theta) :.1+square=square