The acceleration dula to gravity on the surface of moon is `1.7ms^(-2)` . What is the time period of a simple pendulum on the surface of moon if its time period on the surface of earth is 3.5s ?

The acceleration due to gravity on the surface of moon is 1.7 m s^(-2) . What is the time period of a simple pendulum on the surface of moon if its time period on the surface of earth is 3.5 s ? (g on the surface of earth is 9.8 m s^(-2) )

The acceleration due to gravity on the surface of moon is 1.7 ms ^-2 . What is the time period of a simple pendulum on the surface of moon if its time period of the surface of earth is 3.5 s ? (g on the surface of the earth is 9.8 ms^-2

The acceleration due to gravity on the surface of the moon is 1.7ms^(-2) . What is the time perioid of a simple pendulum on the surface of the moon, if its time period on the surface of earth is 3.5s ? Take g=9.8ms^(-2) on the surface of the earth.

The acceleration due to gravity on the surface of the moon is 1.7ms^(-2) . What is the time perioid of a simple pendulum on the surface of the moon, if its time period on the surface of earth is 3.5s ? Take g=9.8ms^(-2) on the surface of the earth.

The acceleration due to gravity on the surface of the moon is 1.7ms^(-2) . What is the time perioid of a simple pendulum on the surface of the moon, if its time period on the surface of earth is 3.5s ? Take g=9.8ms^(-2) on the surface of the earth.