Lights of wavelenths `lambda_(1)=340nm` and `lambda_(2)=540nm` are incident on a metallic surface. If the ratio of the maximum speeds of electrons ejected is 2, the work function of the metal is

Illuminating the surface of a certain metal alternately with light of wavelengths lambda_(1)=0.35 mu m and lambda-(2) =0.54 pm , it was found that the corresponding maximum velocities of photo electrons have a ratio eta = 2. Find the work function of that metal:

Illuminating the surface of a certain metal alternatively with light of wavelength lambda_(1)=0.35 mu m and lambda_(2)=0.54 mu m , it was found that the corresponding maximum velocities of photo electrons have a ratio eta=12 . Find the work function of that metal.

Illuminating a metal surface alternately with wavelengths lambda_1 and lambda_2, when lambda_1 lt lambda_2, it is observed that corresponding ratio of maximum velocities of electrons is equal to n. Then work function of metal is

Illuminating a metal surface alternately with wavelengths lambda_1 and lambda_2, when lambda_1 lt lambda_2, it is observed that corresponding ratio of maximum velocities of electrons is equal to n. Then work function of metal is

Light rays of wavelength lambda and lambda/2 are incident on a a photosensitive metal surface, IF the maximum kinetic energy of the emitted photoelectrons from the metal surface in 2nd case be 3 times the maximum kinetic energy of emitted photoelectrons in the 1st case then determine the work function of the metal.

Surface of certain metal is first illuminated with light of wavelength lambda_(1)=350 nm and then, by light of wavelength lambda_(2)=540 nm. It is found that the maximum speed of the photo electrons in the two cases differ by a factor of 2. The work function of the metal (in eV) is close to : (Energy of photon =(1240)/(lambda("in nm"))Ev

Surface of certain metal is first illuminated with light of wavelength lambda_(1)=350 nm and then, by light of wavelength lambda_(2)=540 nm. It is found that the maximum speed of the photo electrons in the two cases differ by a factor of 2. The work function of the metal (in eV) is close to : (Energy of photon =(1240)/(lambda("in nm"))Ev