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Find out the percentage dissociation of an acid having conc. Of 10 M and dissociation constant `1.0xx10^(-3)`.

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Acetic acid tends to form dimer due to formation of intermolcular hydrogen bonding. 2CH_(2)COOHhArr(CH_(3)COOH)_(2) The equilibrium constant for this reaction is 1.5xx10^(2)M^(-1) in benzene solution and 3.6xx10^(-2) in water. In benzene, monomer does not dissociate but it water, monomer dissociation simultaneously with acid dissociation constant 2.0xx10^(-5) M. Dimer does not dissociate in benzene as well as water. The pH of 0.1M acetic acid solution in water, considering the simultaneous dimerisation and dissociation of acid is :

Acetic acid tends to form dimer due to formation of intermolcular hydrogen bonding. 2CH_(2)COOHhArr(CH_(3)COOH)_(2) The equilibrium constant for this reaction is 1.5xx10^(2)M^(-1) in benzene solution and 3.6xx10^(-2) in water. In benzene, monomer does not dissociate but it water, monomer dissociation simultaneously with acid dissociation constant 2.0xx10^(-5) M. Dimer does not dissociate in benzene as well as water. The pH of 0.1M acetic acid solution in water, considering the simultaneous dimerisation and dissociation of acid is :

Acetic acid tends to form dimer due to formation of intermolcular hydrogen bonding. 2CH_(2)COOHhArr(CH_(3)COOH)_(2) The equilibrium constant for this reaction is 1.5xx10^(2)M^(-1) in benzene solution and 3.6xx10^(-2) in water. In benzene, monomer does not dissociate but it water, monomer dissociation simultaneously with acid dissociation constant 2.0xx10^(-5) M. Dimer does not dissociate in benzene as well as water. The pH of 0.1M acetic acid solution in water, considering the simultaneous dimerisation and dissociation of acid is :

Calculate the degree of ionization of 0.1 M acetic acid. The dissociation constant of acetic acid is 1.8 xx 10^(-5)

The degree of dissociation of acetic acid in a 0.1 M solution is 1.32xx10^(-2) , find out the pKa :-