If a random variable "X" takes values `((-1)^(k)2^(k))/k, k=1,2,3,...` with probabilities `P(X=k)=(1)/(2^(k))`, then E(X)

A random variable X takes the values 0,1,2,3,..., with prbability PX(=x)=k(x+1)((1)/(5))^x , where k is a constant, then P(X=0) is.

If the probability function of a random variable X is defined by P(X=k) = a((k+1)/(2^k)) for k= 0,1,2,3,4,5 then the probability that X takes a prime value is

For a random variable X if P(X=k) = 4((k+1)/5^k)a , for k=0,1,2,…then a= _____

The range of random variable X={1,2,3,....oo} and the probabilities are given by P(x=k)=(C^(k))/(|__k) . Then C=

A random variable X can attain only the value 1,2,3,4,5 with respective probabilities k,2k,3k,2k,k. if m is the mean of the probability distribution, then (k,m) is equal to

The range of a random variable X is 1,2,3,..., and P(X=k)=(c^(k))/(k!) where k=1,2,3... .Find the value of P(0ltXlt3)

A discrete random variable X can take all possible integer values from 1 to K each with a probability (1)/(K) Its variance is

A random variable x has its range {0,1,2} and the probabilities are given by P(x=0) =3k^(3), P(x=1) =4k-10k^(2) , P(x=2) =5k-1 where k is a constant then k=