The inclination of the tangent at `theta=(pi)/(3)` on the curve `x=a(theta+sin theta)`,`y=a(1+cos theta)` is

The equation of tangent to the curve x=a(theta+ sin theta), y=a (1+ cos theta)" at "theta=(pi)/(2) is

If ST and SN are the lengths of the subtangent and the subnormal at the point theta=(pi)/2 on the curve x=a(theta+sin theta),y=a(1-cos theta),a!=1 then

Find the equation of tangent to the curve x=a(theta+sin theta),y=a(1-cos theta) at a point theta

Find the length of normal to the curve x=a(theta+sin theta),y=a(1-cos theta) at theta=(pi)/(2)

The slope of the normal to the curve x=a(theta-sin theta),y=a(1-cos theta) at theta=(pi)/(2)

The angle made by the tangent to the curve x=a(theta + sin theta cos theta),y=a(1+ sin theta)^(2) wutg X-axis is

The length of normal to the curve x=a(theta+sin theta), y=a(1-cos theta), at theta=(pi)/(2) is

The coordinates of the points on the curve x=a(theta+sin theta),y=a(1-cos theta), where tangent is inclined an angle (pi)/(4) to the x -axis are- (A) (a,a)(B)(a((pi)/(2)-1),a)(C)(a((pi)/(2)+1),a)(D)(a,a((pi)/(2)+1))