Mr. B has two fair 6-sided dice, one whose faces are numbered 1 to 6 and the second whose faces are numbered 3 to 8. Twice, he randomly picks one of dice (each dice equally likely) and rolls it. Given the sum of the resulting two rolls is 9, The probability he rolled same dice twice is `(m)/(n)` where m and n are relatively prime positive integers. Then the value of (m+n) is

If the probability that the product of the outcomes of three rolls of a fair dice is a prime number is p ,then the value of 1/(4p) is

A dice is rolled, what is the probability of even numbered outcomes

.When rolling a certain unfair six sided die with faces numbered 1,2,3,4,5&6 the probability of obtaining a specified face F is greater than 1/6 & the probability of the face opposite to it is less than 1/6. The probability of obtaining other four faces are each equal to 1/6 & the sum of the numbers on opposite faces is 7 .When two such die are rolled the probability of obtaining a sum of 7 is 47/288 .If the probability of obtaining the face F is m/n where m&n are relatively prime positive integers then (m+n)=

3 fair dice are rolled and given that atleast two of them show the same number.Find the probability that atleast one die show 4.

The expected value of the sum of the two numbers obtained when two fair dice are rolled is

In rolling of two fair six dice,probability of getting total 5 is: