In the arrangement shown in figure `m_(1)=1kg, m_(2)=2kg`, pullyes are massless and strings are light. For what value of M the mass `m_(1)` moves with constant velocity? (Neglect friction)

In the arrangement shown in fig. m_(1)=1kg, m_(2)=2 kg . Pulleys are massless and strings are light. For what value of M, the mass m_(1) moves with constant velocity.

In the arrangment as shown below m_(1) = 1 kg, m_(2) = 2 kg . Pulleys are massless and strings are light . For what value of M the mass m_(1) moves with constant velocity . ( Neglect Friction)

In the system shown in figure m_(B)=4kg , and m_(A)=2kg . The pulleys are massless and friction is absent everywhere. The acceleration of block A is.

In the arrangement shown in Figure, m_A=2kg and m_B=1kg . String is light and inextensible. Find the acceleration of centre of mass of both the blocks. Neglect friction everywhere.

In the arrangement shown the fixed pulley is massless and frictionless. If the acceleration of block of mass 1kg is (30)/(x)m//s^(2) . Find the value of x .

In the arrangement shown in figure pulleys are mass of block A,b and C is m_(1) = 5 kg m_(2) = 4 kg and m_(3) = 2.5 kg respectively .Co-efficient acceleration of friction for both the plane is mu = 0.50 Calculate acceleration of which block when system is released from rest

In the system shown in fig., all pulleys are mass less and the string is inextensible and light. (a) After the system is released, find the acceleration of mass m_(1) (b) If m_(1) = 1 kg, m_(2) = 2 kg "and" m_(3) = 3 kg then what must be value of mass m_(4) so that it accelerates downwards?

Three blocks of masses m_(1), m_(2) and M are arranged as shown in figure. All the surfaces are fricationless and string is inextensible. Pulleys are light. A constant force F is applied on block of mass m_(1) . Pulleys and string are light. Part of the string connecting both pulleys is vertical and part of the strings connecting pulleys with masses m_(1) and m_(2) are horizontal. {:((P),"Accleration of mass " m_(1),(1) F/(m_(1))),((Q),"Acceleration of mass" m_(2),(2) F/(m_(1)+m_(2))),((R),"Acceleration of mass M",(3) "zero"),((S), "Tension in the string",(4) (m_(2)F)/(m_(1)+m_(2))):}

In the arrangement shown in figure pulley P can move whereas other two pulleys are fixed. All of them are light. String is light and inextensible. The coefficient of friction between 2 kg and 3 kg block is mu = 0.75 and that between 3 kg block and the table is mu = 0.5 . The system is released from rest (i) Find maximum value of mass M, so that the system does not move. Find friction force between 2 kg and 3 kg blocks in this case. (ii) If M = 4 kg, find the tension in the string attached to 2 kg block. (iii) If M = 4 kg and mu_(1) = 0.9 , find friction force between the two blocks, and acceleration of M. (iv) Find acceleration of M if m_(1) = 0.75, m_(2) = -0.9 and M = 4 kg.