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the work done by friction in 10 s is...

the work done by friction in 10 s is

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A body of mass 2 kg initially at rest moves under the action of an applied horizontal force of 7N on a table with coefficient of kinetic friction =0.1 . Calculate the (a) work done by applied force in 10s. (b) work done by friction in 10s. (c ) work done by the net force on the body in 10s. (d) change in K.E. of body in 10s, and interpret your result.

If accelerated pure rolling is taking place on a stationary ground, then work done by friction is always zero, comment on this.

Consider the system shown in the figure. Coefficient of friction between the block and table is mu=0.5. The system is released from rest. Find the work done by friction, when the speed of block is 10 m/s (m=1kg)

A plank of mass 10 kg and a block of mass 2 kg are placed on a horizontal plane as shown in the figure. There is no friction between plane and plank. The coefficient of friction between block and plank is 0.5 .A force of 60 N is applied on plank horizontally. In first 2 s the work done by friction on the block is

A body is thrown on a rough surface such that the friction force acting on it is linearly varying with the distance travelled by it as f=ax+b . Find the work done by the friction on the box if before coming to rest the box travels a distance s.

In the previous question, if agtmu_sg , find the work done by friction on the block during time t.

When a body is rolling without slipping on a rough horizontal surface, the work done by friction is :

A small block of mass 1 kg is kept on a rough inclined wedge of inclination 45^@ fixed in an elevator. The elevator goes up with a uniform velocity v=2 m//s and the block done not slide on the wedge. Find the work done by the of friction on the block in 1s . (g=10 m//s^(2))