Instantaneuous linear momentum of an object is given by `p=(t^(2)+4t+10)` SI unit. At `t=2s` ,Force,`F` will be equal to -

The angular momentum of a body is given by L= (4t^(2)+2t+7)kgm^(2)s^(-1) .The net torque acting on the body at t=2s is

A particle moves along x-axis and its displacement at any time is given by x(t) = 2t^(3) -3t^(2) + 4t in SI units. The velocity of the particle when its acceleration is zero is

The velocity of an object is given by vecv = ( 6 t^(3) hati + t^(2) hatj) m//s) . Find the acceleration at t = 2s.

The momentum p of an object varies with time (t) as shown in figure. The corresponding force (F)- time (t) graph is -

The linear momentum of a particle is given by vec(P)=(a sin t hati- acos t hatj) kg- m//s . A force vec(F) is acting on the particle. Select correct alternative/s:

If the relation between acceleration and time for an object is given by a=2t+4t^(2) Calculate the position of object from the origin at t = 4 s. Assume the object to be at rest at t=0 .

The distance covered by an object (in meter) is given by s=8 t^(3)-7t^(2)+5t Find its speed at t = 2 s.

Linear momentum of an object can be expressed as vecP= (4 cos t)hati+( 4 sin t)hatj . Angle between the forces acting on the object and its linear momentum is :

The linear momentum p of a particle is given as a function of time t as p=At^2+Bt+C .The dimensions of constant B are

The displacement s of an object is given as a function of time t s=5t^(2)+9t Calculate the instantaneous velocity of object at t = 0.