Home
Class 12
PHYSICS
Two very small particles are executing S...

Two very small particles are executing `SHM` along very near parallel lines about the same mean position, same amplitude and the same frequency. At `t = 0` both the particle are moving with speed of `1m//sec` but on the opposite side of the mean position and having same direction of velocity at a distance of `5cm` from the mean position. At `t = 4sec` they are at the same position moving with speed of `1m//sec` but in opposite direction. Assuming that this is the minimum time form `t = 0` where they are meeting for the `1st` time. If the maximum speed of either particle is `(xpi)/(4sqrt(2))cm//sec` Find `x`

Promotional Banner

Similar Questions

Explore conceptually related problems

When a particle executing a linear S.H.M. moves from its extreme position to the mean position, its

The particle performing S.H.M. along a straight line about the mean position with an amplitude 'A'. Then the maximum potential energy at a distance A from the extreme position is

The amplitude and the periodic time of a S.H.M. are 5 cm and 6 sec respectively. At a distance of 2.5 cm away from the mean position, the phase will be

Two particle undergoes SHM along parallel line with the same time period (T) and equal amplitude At a particular instant , one particle is at its extereme position while the other is at its mean position .They move in the same direction .They will cross each other after a further time

The particle is executing SHM on a line 4 cm long. If its velocity at mean position is 12 m/s , then determine its frequency.

Two particles execute S.H.M. along the same line at the same frequency. They move in opposite direction at the mean position. The phase difference will be :

Two particles A and B oscillates in SHM having same amplitude and frequencies f_(A) and f_(B) respectively. At t=0 the particle A is at positive extreme position while the particle B is at a distance half of the amplitude on the positive side of the mean position and is moving away from the mean position.

The particle is executing S.H.M. on a line 6 cms long. If its velocity at mean position is 12 cm/sec, its frequency in Hertz will be:

A particle executes simple harmonic motion with an amplitude of 4cm At the mean position the velocity of tge particle is 10 earth distance of the particle from the mean position when its speed 5 point is