If the sides and angles of a plane triangle vary in such a way that its circumradius remains constant then that `(da)/cosA+(db)/cosB+(dc)/cosC=`

If the sides and angles of a plane triangle vary in such a way that its circumradius remains constant then that (da)/(cos A)+(db)/(cos B)+(dc)/(cos C)=

If the sides of a triangle ABC vary slightly in such a way that 'R' (circum radius) is constant then delta a sec A+delta b .sec B+delta c*sec C=

If the angles of a triangle are in the ratio 1:2:3 and its circumradius is 10 cm, find the sides of the triangle (in cm):

If a triangle ABC ,inscribed in a fixed circle,be slightly varied in such away as to have its vertices always on the circle,then show that (da)/(cas A)+(db)/(cos B)+(dc)/(cos C)=0

In Delta ABC , the side c and angle C are constant. If there are small changes in the remaining sides and angles, then show that (da)/(cos A) +(db)/(cos B)= 0 .

If the sides of a triangle are in the ratio 1 : sqrt(3) : 2, then its angles are in the ratio

If in a triangle ABC, the side c and the angle C remain constant,while the remaining elements are changed slightly,show that (da)/(cos A)+(db)/(cos B)=0

If in a triangle ABC, the side c and the angle C remain constant,while the remaining elements are changed slightly,using differentials show that (da)/(csA)+(db)/(cos B)=0

If the lengths of the sides of a triangle are 3, 5, 7 , then its largest angle of the triangle is