The velocity of a particle in `S.H.M.` at positions `x_(1)` and `x_2` are `v_(1)` and `v_(2)` respectively. Determine value of time period and amplitude.

A particle is executing SHM along a straight line. Its velocities at distances x_(1) and x_(2) from the mean position are v_(1) and v_(2) , respectively. Its time period is

A particle executing linear S.H.M. has velocities v_(1) and v_(2) at distances x_(1) and x_(2) respectively from the mean position. The angular velocity of the particle is

A particle is performing harmonic motion if its velocity are v_(1) and v_(2) at the displecement from the mean position are y_(1) and y_(2) respectively then its time period is

For a particle in SHM the amplitude and maximum velocity are A and V respectively. Then its maximum acceleration is

The velocity of a particle performing linear S.H.M. at mean position is v0. What will be its velocity at the mean position when its amplitude is doubled and time period reduced to l /3 ?

A particle executing linear SHM has velocities v_(1) " and " v_(2) at dis"tan"ce x_(1) " and " x_(2) , respectively from the mean position. The angular velocity of the particle is

The velocities of two particles of masses m_(1) and m_(2) relative to an observer in an inertial frame are v_(1) and v_(2) . Determine the velocity of the center of mass relative to the observer and the velocity of each particle relative to the center of mass.

The velocity of a particle is v=v_(0)+gt+ft^(2) .If its position is x=0 at t=0, then its displacement after 1s is

For a particle in S.H.M. if the amplitude of displacement is a and the amplitude of velocity is v the amplitude of acceleration is