A photon of energy `2.5 eV` and wavelength `lambda` falls on a metal surface and the ejected electron have velocity `'v'`. If the `lambda` of the incident light is decreased by `20%` the maximum velocity of the emitted electrons is doubled. The work function of the metal is

What is the effect on the maximum velocity of the emitted electron if the wavelength of the incident light is decreased?

Photons of energy 2.0eV fall on a metal plate and release photoelectrons with a maximum velocity V . By decreasing lambda and 25% the maximum velocity of photoelectrons is doubled. The work function of the metal of the material plate in eV is nearly

When light of energy 2.5 eV falls on a metal surface, the maximum K.E. of the emitted electrons is T. If the radiation of energy 4eV is made incident on the same metal surface, the K.E. of the electrons is doubled. What is the work function of the metal ?

A light of wavelength 600 nm is incident on a metal surface. When light of wavelength 400 nm is incident, the maximum kinetic energy of the emitted photoelectrons is doubled. The work function of the metals is

When light of 2.5 eV falls on a metal surface, maximum kinetic energy of electron is T. If incident radiation of 4 eV falls on same metal surface, maximum kinetic energy of electrons is doubled. The work function of metal is

Light of wavelength 4000 Å is incident on a metal surface. The maximum kinetic energy of emitted photoelectron is 2 eV. What is the work function of the metal surface ?

The velocity of the most energetic electrons emitted from a metallic surface is doubled when the frequecy v of incident radiation is double. The work function of this metal is

When the energy of the incident radiation is increased by 20%, the kinetic energy of the photoelectrons emitted from a metal surface increased from 0.5 eV to 0.8 eV. The work function of the metal is:

A photosensitive surface has work function W_(0)=hv_(0) . If photons of energy 2hv_(0) fall on this surface, the electrons are ejected with a maximum velocity of 4xx10^(6)m//s . When the energy of the incident photon is increased to 5hv_(0) , then maximum velocity of the photoelectrons will be

A photon iof light with lambda = 470nm falls on a metal surface .As a result photoelectron are ejected with a velocity of 6.4 xx 10^(4) ms^(-1) .Find a. The kinetic energy of emited photonelectron b. The work function (in eV) of the metal surface